Homework Help: chemistry 101

Posted by Sam on Tuesday, March 9, 2010 at 11:29am.

Assume you are performing the calibration step of Experiment 8 and you begin with 50 g of water at 20 oC and 50 g of water at 80 oC. After adding the two portions of water into your calorimeter setup and following the procedure outlined in the experiment, you determine the temperature of the mixed portions of water to be 45 oC. What is the heat capacity of the calorimeter?
Assume room temperature is 25 oC.

chemistry 101 - DrBob222, Tuesday, March 9, 2010 at 12:43pm
Some of the water gained heat. The calorimeter gained heat. Some of the water lost heat.
heat gained + heat lost = 0
I would calculate heat lost by water, subtract heat gained by water. The difference is the heat gained by the calorimeter.

heat gained = mass water x specific heat water x (Tfinal-Tinitial).

heat lost = mass water x specific heat water x (Tfinal-Tinitial).

Take the difference. That's the heat gained by the calorimeter = heat capacity x delta (Tfinal-Tinitial).
chemistry 101 - elizabeth, Saturday, October 29, 2011 at 3:27pm
1008 cCal
chemistry 101 - Anonymous, Wednesday, October 31, 2012 at 10:46am
25 cCal

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