A sample of gas of mass 2.929 g occupies a volume of 426 mL at 0degree Cel and 1.00 atm pressure. What is the molecular weight of the gas?
Thanks!
Use PV = nRT
Calcualte n
n= #moles = grams/molar mass
You know n and g, calculate molar mass
How do I know what N is??
n comes from the equation PV = nRT.
You have V, P, T, and you know R (0.08206) . n is the only unknown in that equation.
Don't forget to change T to Kelvin.
K = 273 + Celsius.
18
Well, if you can provide me with the element symbol or the chemical formula of the gas, I can calculate its molecular weight for you. Without that information, my dear friend, I can only make clownishly wild guesses. Maybe it's a gas composed of laughter and confetti particles? In that case, the molecular weight is incalculable and can only be measured in units of pure joy and entertainment!
To find the molecular weight of the gas, we can use the ideal gas law equation:
PV = nRT
Where:
P is the pressure of the gas (in atm)
V is the volume of the gas (in liters)
n is the number of moles of gas
R is the ideal gas constant (0.0821 L·atm/mol·K)
T is the temperature of the gas (in Kelvin)
First, we need to convert the given values:
Mass of the gas = 2.929 g
Volume of the gas = 426 mL = 426/1000 L = 0.426 L (converted to liters)
Temperature = 0 degrees Celsius + 273.15 = 273.15 K
Pressure = 1.00 atm
Next, rearrange the ideal gas law equation to solve for n (number of moles):
n = PV / RT
Substitute the given values into the equation:
n = (1.00 atm * 0.426 L) / (0.0821 L·atm/mol·K * 273.15 K)
Calculate n:
n = 0.00495 mol
Now, to find the molecular weight, we need to calculate the ratio of the mass of gas to the number of moles:
Molecular Weight (MW) = Mass of gas / Number of moles
Substitute the given values:
MW = 2.929 g / 0.00495 mol
Calculate MW:
MW ≈ 591.91 g/mol
Therefore, the molecular weight of the gas is approximately 591.91 g/mol.