You must be referring to
Using bobpursley's formul, he is very seldom wrong,
and my 10 digit display calculator, I got
130.79 or 131 decibels.
No unfortunately this is not the correct answer :(, is there any other way of doing this question?
Does the formula use natural logs perhaps (ln) ?
Was there a formula or relation given?
By how much is our answer off ?
This is an online assignment, we write the answer and the computer system recognizes whether the answer is right or wrong, but doesn't give any hint.
See if this helps:
The instructor gave us the formula 10log E/E0 and this
question told us what EO is so we just plugged it in then
we got rid of the 10 in front of the log by making it equal
to 12 instead of 120.....Someone already gave the equation
to solve earlier in the discussion Consider log(E/10^-12)=12
just solve for E we know that 10^12 = (E/10^-12) as this is
a log of common base ten then from here you solve for E
we also know that 10^-12 is also 1/10^12
hope these hints help
Ok then, if we are just solving
120 = 10log(E/10^-12) then it is easy
divide both sides by 10
12 = log(E(10^12))
which means e(10^12) = 10^12
E = 1
Yes, 1 is the answer. Thanks a lot for your help Reiny :)
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