Calculus
posted by Cassy on .
A point moves along the curve y=(x2)^2 such that the x coordinate is increasing at 2 units per second. At the moment x=1, how fast is its y coordinate changing.

y = (x2)^2
y = x^24x 4
dy = 2xdx  4dx
so,
dy/dx = 2x4
dx/dt = 2
so,
dy/dt = dy/dx dx/dt
= 2(2x4)
= 4x8
for x=1 then
dy/dt = 4(1)8 = 4 units per second