Posted by Natasha on Monday, March 8, 2010 at 11:13pm.
I think you are ok until the last step. At 100 C the entire 5.00 g is soluble. When filtered and placed in an ice bath, you can get all of it back except for 0.53 g (if you have used 100 mL H2O). So the amount recovered is 5.00 - 0.53 = 4.47 grams.
percent recovered is (4.47/5.00)*100 = ??
I have no idea why you divided by 5.5. You started with 5.00, not 5.50 grams.
Oh I just realized, that was a typo, I meant to divide it by the original mass of 5.0
getting 89.4%
Hi i have this exact question however this is the difference:
The solubility of Acetanilide in hot and cold water is:
Temperature.........Solubility in 100ml H20
100C....................5.5g
0C........................0.53g
What is the maximum recovery if 0.15g of acetanilide is recrystallized using a total of 3mL of hot water?
Looking at your answer, i know that my answer is wrong, Do i have to convert the amt of acetanilide used to increase the volume of water used to 100ml? Please tell me how to do this!! Thanks
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