Posted by Raul on Monday, March 8, 2010 at 11:01pm.
A current I = 16 A is directed along the positive xaxis and perpendicular to a magnetic field. A magnetic force per unit length of 0.15 N/m acts on the conductor in the negative ydirection. Calculate the magnitude and direction of the magnetic field in the region through which the current passes.

physics  drwls, Monday, March 8, 2010 at 11:18pm
When the current I and mgnetic field B are perpendicular,
F = B I L
In your case, force per unit length F/L = 0.15 N/m; therefore
B = (0.15 N/m)/16 A = 9.4*10^3 Tesla
The direction of the field is the z direction. As to whether it is up or down, use the righthand rule to get the direction of I x B, and make sure it is in the y dorection
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