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September 2, 2014

September 2, 2014

Posted by **Kelsey** on Monday, March 8, 2010 at 8:47pm.

Since the pulley is a disk that means I = 1/2mr^2 and omega is vfinal/r. I have my equation 1/2(m2 + m1)vfinal^2 + 1/2Iw^2 = m1gh but I don't know what I'm doing wrong.

- Physic -
**bobpursley**, Monday, March 8, 2010 at 8:54pmSolve for I in that equation, then from

knowing the value of I, set it equal to 1/2 masspulley*radius^2 and solve for the masso of the pulley. radius pulley=.12m

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