Homework Help: Chemistry

Posted by stocihs hard on Monday, March 8, 2010 at 7:17pm.

Lead(II) nitrate reacts with potassium iodine to produce lead(II) iodide and Potassium nitrate. If 1.23 mg of lead nitrate are consumed, what is the mass of the potassium nitrate produced?

Chemistry - DrBob222, Monday, March 8, 2010 at 7:43pm
Pb(NO3)2 + 2KI ==> PbI2 + 2KNO3

Convert 1.23 mg Pb(NO3)2 to moles. moles = grams/molar mass

Using the coefficients in the balanced equation, convert moles Pb(NO3)2 to moles KNO3.

Now convert moles KNO3 to grams. g = moles x molar mass.
Chemistry - Anonymous, Tuesday, November 6, 2012 at 8:00pm
It is reversible I am a high school teacher

Answer this Question

Related Questions

Chemistry - Lead(II) nitrate solution reacts with potassium iodide solution to ...
Chemistry - A reaction was run where lead nitrate and potassium iodide were ...
Chemistry - 50.00 mL samples of 0.200 mol/L potassium phosphate with an excess ...
chemistry - I balanced an equation between lead(II) nitrate and potassium ...
Chemistry help!!! - The class will react 50.00 mL samples of .200 mol/L ...
Chemistry - a class reacts 50.00ml samples of 0.200 mol/L potassium phosphate ...
12th grade-chemistry - what mass of lead (ii) iodide (pbl2, mass=461 amu)is ...
chemistry - Aqueous silver nitrate reacts with aqeous potassium iodide in a ...
Chemistry - If 32.0 mL lead(II) nitrate solution reacts completely with excess ...
Lead Nitrate - I want to make a 10% Lead Nitrate Reagent solution. How do I ...

For Further Reading

First Name:
School Subject:
Answer: