posted by stocihs hard on .
Lead(II) nitrate reacts with potassium iodine to produce lead(II) iodide and Potassium nitrate. If 1.23 mg of lead nitrate are consumed, what is the mass of the potassium nitrate produced?
Pb(NO3)2 + 2KI ==> PbI2 + 2KNO3
Convert 1.23 mg Pb(NO3)2 to moles. moles = grams/molar mass
Using the coefficients in the balanced equation, convert moles Pb(NO3)2 to moles KNO3.
Now convert moles KNO3 to grams. g = moles x molar mass.
It is reversible I am a high school teacher