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posted by Katelynn on Monday, March 8, 2010 at 7:07pm.

Determine the pH of 0.18M NH4Cl.

NH4^+ + H2O ==> H3O^+ + NH3 Ka = (Kw/Kb) = (NH3)(H3O^+)/(NH4^^+) Set up an ICE chart and solve for (H3O^+), then convert to pH.

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