Posted by ALan on Monday, March 8, 2010 at 7:01pm.
You need to solve two simultaneous equations for R1 and R2.
The first is the geometrical relation:
R2 = R1 + 5/tan 60 = R1 + 2.89 m
The second is the physics relation:
pi*R2^2 * Po =
pi*R1^2 (Po + rho*g*depth)
Po = atmospheric pressure = 1.01*10^5 Pa
rho*g*depth = 0.49*10^5 Pa
R2^2/R1^2 = 1.50/1.01 = 1.49
R2/R1 = 1.22
Take it from there.
o wow, i didnt even think of the geometrical way, thanks.
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