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August 27, 2014

August 27, 2014

Posted by **DK** on Monday, March 8, 2010 at 6:20pm.

5y10 - 31y5 - 28

- Math -
**Reiny**, Monday, March 8, 2010 at 6:39pmYou must have meant to type

5y^10 - 31y^5 - 28

then ... let y^5 = x

5x^ - 31x - 28

= (x-7)(5x + 4)

= (y^5 - 7)(5y^5 + 4)

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