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posted by DK Monday, March 8, 2010 at 6:20pm.
Factor by introducing an appropriate substitution. 5y10 - 31y5 - 28
You must have meant to type 5y^10 - 31y^5 - 28 then ... let y^5 = x 5x^ - 31x - 28 = (x-7)(5x + 4) = (y^5 - 7)(5y^5 + 4)
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