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January 25, 2015

January 25, 2015

Posted by **bill** on Monday, March 8, 2010 at 6:08pm.

- trigonometry -
**Reiny**, Monday, March 8, 2010 at 6:32pmmake a sketch, label the side across from the 33º angle as x, and the side across the 62º as y.

Using the sine law

x/sin33 = 25/sin85

do y the same way.

draw a perpendicular from the boat to shore, giving you a right-angled triangle, call it h

sin 62 = h/x

h = xsin62, and since we know x ....

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