Posted by bill on Monday, March 8, 2010 at 6:08pm.
make a sketch, label the side across from the 33º angle as x, and the side across the 62º as y.
Using the sine law
x/sin33 = 25/sin85
do y the same way.
draw a perpendicular from the boat to shore, giving you a right-angled triangle, call it h
sin 62 = h/x
h = xsin62, and since we know x ....
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