Posted by Sandhya on Monday, March 8, 2010 at 10:55am.
For an exact solution, apply the Biot-Savart law, which is explained at
http://en.wikipedia.org/wiki/Biot%E2%80%93Savart_law
and many other places. You can save time by applying it for the field due to a wire length on one side of the square, and multiplying by 4 x 120. Each of the four sides wil contribute equally to the B field in the middle of the loop.
Related Questions
p - A square ammeter has sides of length l = 3.75 cm. The sides of the ammeter ...
Physics - A coil is made up of 19 square loops with the sides equal to 5.3 cm. ...
physics - A high-voltage power line carries a current of 120 A at a location ...
Physics - 1)An increase in the velocity of wire moving perpendicular through a ...
physics - An insulated copper wire is wrapped around an iron nail. The resulting...
physics - if you have two separate current carrying loops of wire in the xz ...
physics - A wire of length 0.655 m carries a current of 21.0 A. In the presence ...
PHYSICS - A square wire loop 10.0 cm on each side carries a clockwise current of...
PHYSICS - A square wire loop 10.0 cm on each side carries a clockwise current of...
College physics - The magnetic field at the center of a 0.70-cm-diameter loop is...
For Further Reading
