How many coulombs of positive charge are in 3.8 mol of O2 gas?
Only the ones due to protons in the nuclei, and they are all neutralized by electrons surrounding the molecules.
If they want the charge in nuclei, for 3.8 moles, that would be
3.8*32*e*(Avogadro's number)
I came out with 1.99e26 and I got it wrong. What is the point of multiplying by e?
They are asking for charge (in Coulombs), not the number of protons. +e is the charge of one proton.
So I need to multiply by 10 not e? Is that right? So the answer should be 7.32e26
To determine the number of coulombs of positive charge in 3.8 mol of O2 gas, we need to consider the number of moles of oxygen molecules (O2) and the charge of each oxygen atom.
The formula for oxygen gas (O2) tells us that each molecule consists of two oxygen atoms. Since oxygen is found in nature as diatomic molecules, we'll need to calculate the number of oxygen atoms in 3.8 mol of O2.
The Avogadro's number (6.022 x 10^23) represents the number of particles (atoms, molecules, or ions) in one mole of any substance. Therefore, to determine the number of oxygen atoms in 3.8 mol of O2, we use the following calculation:
Number of oxygen atoms = number of moles of O2 x Avogadro's number
= 3.8 mol x 6.022 x 10^23 atoms/mol
Now, since each oxygen atom carries a charge of -2 (as per its valence), we need to multiply the number of oxygen atoms by the magnitude of the charge to get the total positive charge:
Total positive charge = number of oxygen atoms x charge on each oxygen atom
= (number of oxygen atoms) x (-2)
Putting it all together, we can calculate the number of coulombs of positive charge:
Total positive charge = (3.8 mol x 6.022 x 10^23 atoms/mol) x (-2)
= 4.5812 x 10^24 coulombs
Therefore, there are 4.5812 x 10^24 coulombs of positive charge in 3.8 mol of O2 gas.