Posted by GGIFT on Monday, March 8, 2010 at 8:14am.
When performing operations, like "squaring both sides", sometimes roots are introduced that were not part of the original relation.
e.g.
let x = 4, and only 4
square both sides
x^2 = 16
now take √
√(x^2) = √16
± x = 4
x = ±4 , we now a "new" root
So inother words, we need to make that solutions are not those of original equations??
I will give you another example
solve √(3x+10) = x+2
square both sides
3x+10 = x^2 + 4x + 4
x^2 + x - 6 = 0
(x+3)(x-2) = 0
x = -3 or x = 2
check: (in original)
if x=2
LS = √(6+10) = √16 = 4
RS = 2+2 = 4 , checks
if x = -3
LS = √(-9+1) = 1
RS = -3+2 = -1 , does not work
so x = 2
I still do not understand it.
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