posted by jake on .
How do I go about in solving this?
A spy satellite is in circular orbit around Earth. It makes one revolution in 6.01 hours.
(a) How high above Earth's surface is the satellite?
(b) What is the satellite's acceleration?
(a) Set the centripetal force equal to the gravity force on the satellite, and solve for R, the distance from the center of the earth.
G*M*m/R^2 = m V^2/R
M is the mass of the Earth and G is the universal constant of gravity. The satellite mass m cancels out.
Once you have R, subtract the Earth's radius (Re) from that to get the altitude. You will need the speed V of the satellite. Express V in terms of the orbit radius (R) and the period (6.01 hours). Make sure the period is in seconds.
(b) The acceleration is V^2/R. Use the R and V that you get from part (a)