physics
posted by jake on .
How do I go about in solving this?
A spy satellite is in circular orbit around Earth. It makes one revolution in 6.01 hours.
(a) How high above Earth's surface is the satellite?
___ km
(b) What is the satellite's acceleration?
___m/s2

(a) Set the centripetal force equal to the gravity force on the satellite, and solve for R, the distance from the center of the earth.
G*M*m/R^2 = m V^2/R
M is the mass of the Earth and G is the universal constant of gravity. The satellite mass m cancels out.
Once you have R, subtract the Earth's radius (Re) from that to get the altitude. You will need the speed V of the satellite. Express V in terms of the orbit radius (R) and the period (6.01 hours). Make sure the period is in seconds.
(b) The acceleration is V^2/R. Use the R and V that you get from part (a)