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October 31, 2014

October 31, 2014

Posted by **jake** on Sunday, March 7, 2010 at 11:35pm.

A spy satellite is in circular orbit around Earth. It makes one revolution in 6.01 hours.

(a) How high above Earth's surface is the satellite?

___ km

(b) What is the satellite's acceleration?

___m/s2

- physics -
**drwls**, Monday, March 8, 2010 at 7:51am(a) Set the centripetal force equal to the gravity force on the satellite, and solve for R, the distance from the center of the earth.

G*M*m/R^2 = m V^2/R

M is the mass of the Earth and G is the universal constant of gravity. The satellite mass m cancels out.

Once you have R, subtract the Earth's radius (Re) from that to get the altitude. You will need the speed V of the satellite. Express V in terms of the orbit radius (R) and the period (6.01 hours). Make sure the period is in seconds.

(b) The acceleration is V^2/R. Use the R and V that you get from part (a)

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