Homework Help: physics

Posted by jake on Sunday, March 7, 2010 at 11:34pm.

(how do I go about solving this, i know i need to conver 88days to secs and that would be 126,720. but I don't where to go from there, help please)

What is the average linear speed of Mercury about the Sun? (The distance from the Sun to Mercury is 5.80 1010 meters. The orbital period around the Sun is 88 days.)

physics - drwls, Monday, March 8, 2010 at 7:56am
The speed of Mercury in orbit is
V = 2 pi R/(period). Your conversion of the period to seconds is incorrect. You have apparently converted it to minutes.

Use R = 5.80 10^10 meters as the distance of Mercury from the sun.

Answer this Question

Related Questions

AP Chem - Sorry, I have one other question. How would I go about solving this ...
AP Biology - After an enzyme is mixed with its substrate, the amount of product ...
Math - I need help on two problems. How would you go about solving: 1. 3(a-5) + ...
Math - Hello! I need assistance in solving for a side for a right triangle in ...
Algebra - Explain the difference between solving a linear equation graphically ...
Math puzzle - how would you go about solving this ive tryed everything. 2*2+7*3+...
PHYSICS - A CAR ACCELERATES TO 36M/S FOR 4 SECS BEFORE DECELERATING TO 32M/S FOR...
Calculus - I am having trouble solving this problem: "Find where the ...
Physics - A roller coaster ride includes a circular loop with radius R = 11.6 m...
algerbra - the problem is x+6-2x+9, how would i go about solving it a simpiler ...

For Further Reading

First Name:
School Subject:
Answer: