Posted by **Joseph** on Sunday, March 7, 2010 at 11:26pm.

Hi, I have the following question:

1. The index of refraction for a prism is given by the equation:

n = 1.58 − (6.41 x 10^4)λ

where λ is the wavelength in meters. Light is incident at 28°.

Find the exit angle ß for light of

a) 800 nm

b) 633 nm

c) 540 nm

2. Will lower wavelengths be allowed to exit the prism? Why or why not?

- Physics -
**drwls**, Monday, March 8, 2010 at 8:04am
Use the given wavelength to compute the refractive index at that wavelength, then use Snell's law (twice) to get the refraction angles in and out. You have not said what the angle of the prism is. Shall we assume the cross section is an equilateral triangle? You need to know it when computing the exit angle.

At a wavelength of 540*10^-9 m, the refractive index is 1.545. That is not a lot different from the value at 800 nm, but different enough to disperse a good spectrum. Light incident at any angle will be able to enter the prism, and will find a way to get out somehow.

## Answer This Question

## Related Questions

- Physics - Monochromatic light of wavelength, λ is traveling in air. The ...
- physics - Horizontal rays of red light (λ = 660 nm, in vacuum) and violet ...
- Calculus - My question is finding the derivitive of y=((x+λ)^4)/(x^4+λ...
- Physics - A photon having wavelength λ scatters off a free electron at A (...
- physics - Phy 124 – Chapter 22 Problems 1. Consider the following. A spot on a ...
- Solar - Greeting All, please assist with the below. Thanks. The spectral power ...
- PHYSICS - Two parallel slits are illuminated by light composed of two ...
- probability - lengths of the different pieces are independent, and the length of...
- Physics - Consider a single photon with a wavelength of λ, a frequency of...
- chem - Given the following wavelength of light, calculate the energy of one ...

More Related Questions