Posted by Sara on Sunday, March 7, 2010 at 9:22pm.
This is really two problems in one but it's the same principle as the CH2Cl2 and CH2Br2 EXCEPT it's a little simpler since NaCl is not volatile. It's a non-volatile solute BUT it ionizes into two particles instead of one. You give it a whirl and post your calculations if you come up dry.
No luck with me too. I'm drawing a blank since they don't give you moles or grams to work with. Thank you for all your help!!!
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