Posted by sarah on Sunday, March 7, 2010 at 8:27pm.
a city block 500ft by 500ft is an unobstructed paved lot, except for a small office building 100ft by 100ft, centered in the middle of the block. What's the shortest distance from the SW corner to the NE corner, going through the paved lot and along (but not through) the building (to the nearest foot)?

math  MathMate, Sunday, March 7, 2010 at 8:44pm
The shortest distance from the SW corner of the lot to the NE corner of the lot is along two straight lines which pass through the SE or NW corner of the building.
If the path passes through the SE corner of the building, the xdisplacement is 250+50=300 ft, and the ydisplacement is 25050=200 ft. Find the distance by Pythagoras theorem. Since by symmetry, the other leg has the same length, the total distance is 2√(200²+300²)

math  Ms. Sue, Sunday, March 7, 2010 at 8:45pm
The diagonal (c) across the lot:
500^2 + 500^2 = c^2
250,000 + 250,000 = 500,000^2
c = 707.11 feet
Less the diagonal through the building:
100^2 + 100^2 = c^2
10,000 + 10,000 = 20,000^2
c = 141.43 feet
707.11  141.42 = 565.69 feet
565.69 + 200 = 765.69 = 766 feet
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