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February 1, 2015

February 1, 2015

Posted by **shawn** on Sunday, March 7, 2010 at 8:07pm.

x^4-16=0

- Math, not "12th grade" -
**Writeacher**, Sunday, March 7, 2010 at 8:10pmAssistance needed.

Please type your__subject__in the**School Subject**box. Any other words, including obscure abbreviations, are likely to delay responses from a teacher who knows that subject well.

- 12th grade -
**Reiny**, Sunday, March 7, 2010 at 8:14pmI would insist that by 12th grade you would recognize the difference of squares pattern.

- Precalculus -
**Alonzo**, Thursday, March 11, 2010 at 1:57pmProblem x4 - 16 = 0

FIRST. Make [x4 - 16] a perfect square.

Dive -16 by two and square that number, add to both sides.

x4 -16 + 64 = 0 + 64

SECOND. Solve the equation.

(Simplify) → (x2 - 8)^2 this equal the left side of the equation.

so we have

(x2 -8)^2 = 64

Then

Remove the square by taking the square root of 64.

x2 - 8 = positive or negative 8

And then find your answers.

- 12th grade -
**Tim**, Sunday, March 28, 2010 at 2:47am(x-2)(x+2)(x^2+4)= 0

Giving the solutions

x= +2;-2;-2i;2i

(i being the imaginary unit)

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