Determine the [H3O+] of a 0.160M solution of benzoic acid.
College Chem II - DrBob222, Sunday, March 7, 2010 at 6:14pm
Benzoic acid = HBz
HBz ==> H^+ + Bz^-
Ka = (H^+)(Bz^-)/(HBz)
Set up an ICE chart, substitute into the Ka expression, and solve for (H^+), then convert to pH. You will need to look up the Ka for benzoic acid.
College Chem II - yesenia, Wednesday, October 2, 2013 at 9:30pm