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August 21, 2014

August 21, 2014

Posted by **Anonymous** on Sunday, March 7, 2010 at 3:32pm.

lim as x-> 1

(x^2 + |x -1| - 1 ) / ( |x-1| )

- calculus -
**drwls**, Sunday, March 7, 2010 at 3:59pmEvaluate the limit approaching 1 from both x>1 and x<1 directins. The x-1 terms will get switched in sign in the latter case.

Use L'Hopital's rule and see if the limit is the same in both directions.

For x-> 1 from above, the limit is 2x + 1 = 3

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