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lim as x-> 1

(x^2 + |x -1| - 1 ) / ( |x-1| )

  • calculus -

    Evaluate the limit approaching 1 from both x>1 and x<1 directins. The x-1 terms will get switched in sign in the latter case.

    Use L'Hopital's rule and see if the limit is the same in both directions.

    For x-> 1 from above, the limit is 2x + 1 = 3

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