Posted by Carrie on Sunday, March 7, 2010 at 12:59am.
Would the total possible outcomes be 17?
The number of evens would be 10 and the multiply of 3 is 7. So 10 and 7 together is 10.
List the numbers from 1 to 21 which are either even or multiples of 3:
2,3,4,6,8,9,10,12,14,15,16,18,20,12
I count 14, not 17.
Prob(event as stated) = 14/21 = 2/3
Ok. I counted some numbers twice. I needed to write the numbers out like you did. Thanks
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