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March 27, 2017

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find the derivative of

y= 3-secx/tanx

  • calculus - ,

    y' = (3-secx)'tanx -(3-secx)(tanx)'/(tanx)^2

    = -secx(tanx)^2 - (3-secx)secx/(tanx)^2

    = -secx[(tanx)^2 + (3-secx)]/tan^2x

    =-[(tan)^2 +3 -secx]/sinx

  • calculus - ,

    Y=-cosxln(secx+tanx)

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