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Posted by Zoey on Saturday, March 6, 2010 at 4:37pm.

find the derivative of y= 3-secx/tanx

y' = (3-secx)'tanx -(3-secx)(tanx)'/(tanx)^2 = -secx(tanx)^2 - (3-secx)secx/(tanx)^2 = -secx[(tanx)^2 + (3-secx)]/tan^2x =-[(tan)^2 +3 -secx]/sinx

Y=-cosxln(secx+tanx)

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