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July 22, 2014

July 22, 2014

Posted by **Zoey** on Saturday, March 6, 2010 at 4:37pm.

y= 3-secx/tanx

- calculus -
**bun**, Saturday, March 6, 2010 at 7:32pmy' = (3-secx)'tanx -(3-secx)(tanx)'/(tanx)^2

= -secx(tanx)^2 - (3-secx)secx/(tanx)^2

= -secx[(tanx)^2 + (3-secx)]/tan^2x

=-[(tan)^2 +3 -secx]/sinx

- calculus -
**joans**, Thursday, August 30, 2012 at 10:29amY=-cosxln(secx+tanx)

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