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March 6, 2015

March 6, 2015

Posted by **Jeff** on Saturday, March 6, 2010 at 4:07pm.

How do you do this... Thanks

- Middle school Math -
**anonymous**, Saturday, March 6, 2010 at 4:10pmI'd love to help, but is there supposed to be an x somewhere in this equation?

like...

3y-4x=11

- Middle school Math -
**anonymous**, Saturday, March 6, 2010 at 4:16pmOk... I'll just assume that the equation is 3y-4x=11.

So the y-intercept of a line is where the graph intersects with the y axis. Any point on the y axis must have an x value of 0. To find the y-intercept of this line, we have to plug in 0 for x and solve for y.

3y=11

y=11/3

The x-intercept is where the line crosses the x axis. And the x intercept should have a y coordinate of 0. So we have to plug in 0 for y and solve for x.

-4x=11

x= -11/4

So the x intercept= 11/3

y intercept= -11/4

I hope you understand this better. Peace.

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