Posted by Jackie on Saturday, March 6, 2010 at 3:55pm.
I assume you mean the integral of e^[(1+i)x] Since 1 + i is a constant, and the integral of e^ax = (1/a)e^ax for any constant a, the integral is e^[(1+i)x]/(1+i) = [(1-i)/2]*e^[(1+i)x]