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July 31, 2014

July 31, 2014

Posted by **Jackie** on Saturday, March 6, 2010 at 3:55pm.

- Calculus -
**drwls**, Saturday, March 6, 2010 at 4:50pmI assume you mean the integral of e^[(1+i)x]

Since 1 + i is a constant, and the integral of e^ax = (1/a)e^ax for any constant a, the integral is

e^[(1+i)x]/(1+i)

= [(1-i)/2]*e^[(1+i)x]

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