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Find an equation of the tangent line to the curve at the given point. (Assume the tangent line form to be f(x) = mx + b.)

y= e^x/x (1,e)

I got m= 0
nd b=e
could anyone tell if its right?

  • Calculus - ,

    y'=d/dx (1/x * e^x)= e^x(-1/x^2+1/x)
    at 1,e
    y'=slope=e(-1+1)=0 correct for m
    y= mx+b=b
    so b=e correct.

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