Posted by **Janus** on Saturday, March 6, 2010 at 11:53am.

5 pounds of an ideal gas with R=38.7 and K=1.668 have 300Btu of heat added during a reversible constant pressure change of state, initial temperature=80°F.

Determine:

a.)the final temperature

b.)change of internal energy

change of enthalpy

change of entropy

- Thermodynamics -
**drwls**, Saturday, March 6, 2010 at 12:34pm
a) Since it is a constant pressure heating, dQ = M Cp dT = [K*M*R/((K-1)]*dT

Use that to determine the temperature changle dT, and add that to 80 F.

You need to specify the units of R. They should be Btu/lbm*degF

b) dU = M Cv dT = [M/(K-1)]dT

c) dH = Cp*dT = dQ

d) dS = Integral of dQ/T

= Integral of M Cp dT/T

= M Cp ln(T2/T1)

The T's must be in degrees Rankine

## Answer This Question

## Related Questions

- chem - A sample of H2(g) expands adiabatically and reversibly from a state 1 ...
- Physics - Suppose 2100 J of heat are added to 3.3 mol of argon gas at a constant...
- Chemistry - 2 moles of ideal gas at 300K, initial volume 25 L, are compressed ...
- chemistry - the pressure of 3moles of an ideal gas in a container is reduced ...
- physics - An ideal gas is in equilibrium at initial state with temperature T=...
- physics help please - Consider a system in which 3.60 mol of an ideal monatomic...
- thermodynamics - A piston-cylinder device contains 100 g of ethylene gas ...
- Chemistry - The phrase “the heat absorbed or released by a system undergoing a ...
- thermodynamics - A scuba tank contains 1.5 kg. of air. The air in the tank is ...
- physics - The temperature of 7.10 mol of an ideal monatomic gas is raised 15.0 K...

More Related Questions