Posted by **clyde** on Friday, March 5, 2010 at 10:25pm.

While exploring a cave, a spelunker starts at the entrance and moves the following distances: 75.0 m north, 275 m east, 160 m at an angle 30.0° north of east, and 150 m south. Find the resultant displacement from the cave entrance.

- tsu ??? -
**Ms. Sue**, Friday, March 5, 2010 at 10:35pm
What __School __**Subject** is tsu?

- vector addition -
**drwls**, Saturday, March 6, 2010 at 5:52am
The net north displacement is:

75 +80 sin 30 - 150 = -35. or 35 m south

The net eastward displacement is 275 + 160 cos 30 = 413.6 m

The total distance moved is given by

D^2 = (35)^2 + (413.6)^2

D = 415.0 m

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