Posted by clyde on Friday, March 5, 2010 at 10:25pm.
What School Subject is tsu?
The net north displacement is:
75 +80 sin 30 - 150 = -35. or 35 m south
The net eastward displacement is 275 + 160 cos 30 = 413.6 m
The total distance moved is given by
D^2 = (35)^2 + (413.6)^2
D = 415.0 m
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