Sunday

September 21, 2014

September 21, 2014

Posted by **Hannah** on Friday, March 5, 2010 at 6:31pm.

tanx - sec^2x/tanx

tan^2(x)/tan(x) - sec^2x/tanx =

tan^2x sec^2x / tanx

then I use the identity 1+tan^2u=sec^2u

I do not know what to do at this point.

- Pre-Cal -
**Reiny**, Friday, March 5, 2010 at 6:40pmfrom you second line

tan^2(x)/tan(x) - sec^2x/tanx

= (tan^2 x - sec^2 x)/tanx

= (tan^2 x - (1 + tan^2 x))/tanx

= -1/tanx or -cotx or -sinx/cosx

**Answer this Question**

**Related Questions**

calculus - find dy/dx y=ln (secx + tanx) Let u= secx + tan x dy/dx= 1/u * du/dx ...

Integration - Intergrate ¡ì sec^3(x) dx could anybody please check this answer. ...

Calculus - Integration - Hello! I really don't think I am understanding my calc ...

Trigonometry - Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b...

Trigo - Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in ...

Pre Cal - could someone please tell me what the other angle identity of tan is? ...

Calc - Hello im trying to integrate tan^3 dx i have solved out the whole thing ...

Calc - Hello im trying to integrate tan^3 dx i have solved out the whole thing ...

Calculus - Int tanx sec^2x dx can be taken as (by putting it in form of Int xdx...

trigonometry (please double check this) - Solve the following trig equations. ...