Thursday

November 27, 2014

November 27, 2014

Posted by **Jill** on Friday, March 5, 2010 at 11:48am.

I will try and describe the Graph.

-It starts at the origin (0,0)

-It has a minimum value of -2

-It has a maximum value of 2.

-It has an x-intercept of 90 degrees.

-It starts moving downward below the x-axis, and then curves back upwars, and continues in this pattern.

My answer:

I think "a" should= 2.5, but I do not not what "b" should be. Whatever I put in, I can not get the graph to start at the origin. It always starts above or below y=0.

Could someone please help me?

Thanks.

- Math -
**Reiny**, Friday, March 5, 2010 at 2:03pmA cosine curve without a phase shift cannot start at (0,0)

The curve that would fit your description would have to be**y = 2cos 2(x + 45 degrees)**

Check:

(0,0) lies on it.

when x = 90, y = 2 cos 270 = 0

so there is an x-intercept at 90

when x=45, y = 2 cos 180 = -2

when x = 135, y = 2 cos 360 = +2

the period of the curve is 180 , shown by b=2

**Answer this Question**

**Related Questions**

Math - Determine the equation of the graph in the form y = acos(bx). I will try ...

physics - How far from the origin is the puck after 5 seconds (m)? Since I cant ...

Precalculus - Whats the value of a? =-= For the graph, determine the equation of...

calculus - I have two questions, please help. 1. Determine the quadratic ...

calculus - I have two questions, please help. 1. Determine the quadratic ...

Physics - a graph of an object moving a line (+ axes)on acceleration-time graph...

math - Consider the cubic graph y = 3x^2 − x^3. (a) Write 3x^2 − x^3...

precalculus - How do I find the vertical/horizontal compression/stretch? For the...

Calculus - Functions? - #1. A cubic polynomial function f is defined by f(x) = ...

Math - I have a graph which I need to find the equation of. It's an absolute ...