Posted by Jake on Thursday, March 4, 2010 at 11:40pm.
The figure below
shows an arrangement of 15 identical disks that have been glued together in a rodlike shape of length L = 1.4500 m and (total) mass M = 135.000 g. The arrangement can rotate about a perpendicular axis through its central disk at point O.
(a) What is the rotational inertia of the arrangement about that axis?
(b) If we approximated the arrangement as being a uniform rod of mass M and length L, what percentage error would we make in using the formula in Table 102e to calculate the rotational inertia?
%
the formula given is I=1/12 ML^2

Physics.  drwls, Friday, March 5, 2010 at 7:56am
I don't quite get the picture here. The exact moment of inertia, for rotation about an axis that is perpendicular to the axis of the gluedtogether rod, will depend upon the diameter of the discs as well as the length of the rod. I don't get the significance of the number of discs, since they are glued together into one road.
The formula I = (1/2) m L^2 applies to a rod that is very narrow compared to its length, and rotated about its center, about an axis PERPENDICULAR to the axis of the rod

Physics.  Anonymous, Saturday, January 28, 2017 at 4:02pm
Use parallel axis theorem for each individual particle
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