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October 1, 2014

October 1, 2014

Posted by **Kyler** on Wednesday, March 3, 2010 at 3:03pm.

- Trig. -
**drwls**, Wednesday, March 3, 2010 at 3:13pmL.H. Side:

2 csc(2x) = 2/sin(2x)

= 1/(sinx cosx)

R.H. side:

csc(x)^2 tan x = (1/sin^2x)(sinx/cosx)

= 1/(sinx cosx)

q.e.d.

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