Posted by anonymous on Wednesday, March 3, 2010 at 5:51am.
This is an exercise in adding vectors. The ratio of components in vector sum will provide the fdirection information you need. The mass is the ratio of the force magnitude to the acceleration.
For (c), assume the initial speed is zero and multiply the acceleration and time interval. For (d), multiply the vector acceleration by the time.
Show your work if further assistance is needed.
a) direction of acceleration in the same way as resultant force, hence
Fr=F1+F2+F3=(-1.85-5.10-45.0)i+(2.50+3.25+48.0)j= -51.95i+53.75j [N]
θ=tanˉ¹(53.75/-51.95)=134°.
b) F=ma --- m=F/a --- (√((-51.95)^2+53.75^2))/3.75=19.9kg
c)Vf=Vi+at=0+3.75*17=63.75m/s
d)F=ma --- a=F/m ---āx=F̅x/m --āy=F̅y/m
ā=āx + āy
V̅f=V̅i+āt=0+((-51.95/19.9)i+(53.75/19.5)j)*10
V̅f=((-51.95/19.9)*10)i+(53.7/19.5)*10)j
V̅f= -26.1i+27.5j
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