Posted by Stan on Wednesday, March 3, 2010 at 1:26am.
Is the 0.540mg 0.540 milligrams or 0.54m * g? I will assume the latter.
For case (a), the maximum possible static friction force is
Fs = (m*g cos16* - 0.54m*g sin16)*Us
= 0.487 m g
The horizontal component of applied force is 0.540m*g*cos 16 = 0.519 m*g. Since this exceeds the maximum possible static friction force, the block slips and accelerates at a rate determined by
kinetic friction.
The friction force in the horizontal direction must be recomputed and subtracted from the applied force component in that direction.
For case (b), proceed similarly
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