Posted by nikki on Wednesday, March 3, 2010 at 1:26am.
Using the inverse of a Matrix:
Let ‘a’ be adults and ‘c’ be children
a + b = 1000
16 a + 8b = 12,800
1 1 1000 -16 R1 (R2) 1 1 1000 R2 / 8
16 8 12800 0 -8 -3200
1 1 1000 -1 R2 + R1 1 0 600
0 1 400 0 1 400
Therefore, there were 600 adults and 400 children on Saturday.
SUNDAY
a + b = 800
16a + 8 b = 9600
1 1 1000 -16 R1 (R2) 1 1 1000 R2 / 8
16 8 12800 0 -8 -3200
1 1 1000 -1 R2 + R1 1 0 400
0 1 400 0 1 400
Therefore there were 400 adults and 400 children on Saturday.
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