An experiment consists of rolling a die and selecting a marble from a bag. the bag has 7 orange, 3 pink, and 6 grey marbles. What is the probability of rolling a multiple of 3 and selecting a pink marble?
Anwer: The two events are independent of each other, therefore we multiply.
For multiple of 3: 1/6 + 1/6 = 1/3
P(E and F)=P(E)*P(F)
= 1/3 * 3/16
=1/16
Can some please check my answer to make sure it is correct?
Thanks
Let's break down the question step by step to check your answer.
We have two events: rolling a die and selecting a marble. The probability of rolling a multiple of 3 is 1/6 because there are 6 possible outcomes on a fair 6-sided die, and exactly 2 of them (3 and 6) are multiples of 3.
Now, the probability of selecting a pink marble depends on the total number of marbles in the bag. In this case, there are a total of 16 marbles in the bag (7 orange + 3 pink + 6 grey).
So, the probability of selecting a pink marble is 3/16 because there are 3 pink marbles out of the total 16 marbles.
Since the two events (rolling a multiple of 3 and selecting a pink marble) are independent, we can multiply the probabilities. Thus, the probability of both events occurring is (1/6) * (3/16) = 3/96 = 1/32.
Therefore, according to the correct calculations, the probability of rolling a multiple of 3 and selecting a pink marble is 1/32.
Your answer, 1/16, seems to be incorrect. The correct probability should be 1/32.