Friday
April 18, 2014

Homework Help: Physics 103

Posted by Kate on Tuesday, March 2, 2010 at 11:20pm.

How do I start?

Problem: A helium nucleus (m= 6.65 x 10^-27 kg and q = 2e)is initially at rest. It is accelerated through a potential difference delta V and then enters a region with a constant magnetic field of strength B= 4T. It enter perpendicular to the field and undergoes circular motion with a radius of 0.001 m. Determine delta V?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Physics - A doubly charged helium atom (mass = 6.68 x 10-27 kg) is accelerated ...
physics - A helium nucleus (charge = 2e, mass = 6.63 10-27 kg) traveling at a ...
Physics - An -particle has a charge of +2e and a mass of 6.64 10-27 kg. It is ...
Physics - An electron, initially at rest is accelerated through a potential ...
Physics - An -particle has a charge of +2e and a mass of 6.64 10-27 kg. It is ...
physics - If a proton is accelerated from rest through a potential difference of...
physics - The electrons in a TV tube are accelerated from rest through a ...
physics - A proton of mass mp = 1.67 x 10-27 kg and charge +e = 1.60 x 10-19 C ...
Physics - (1) A bullet of mass 1.910−3 kg embeds itself in a wooden block...
physics - a proton (mass 1.67 x 10^-27 kg) with a velocity of 1.10 x 10 7 m/s ...

Search
Members