Physics 103
posted by Kate on .
How do I start?
Problem: A helium nucleus (m= 6.65 x 10^27 kg and q = 2e)is initially at rest. It is accelerated through a potential difference delta V and then enters a region with a constant magnetic field of strength B= 4T. It enter perpendicular to the field and undergoes circular motion with a radius of 0.001 m. Determine delta V?

Use the formula for the Larmor radius to get the velocity, v. You will find it at
http://en.wikipedia.org/wiki/Gyroradius
Then compute the kinetic energy of the particle, KE = (1/2) m v^2
Use that to get deltaV
KE = q*(deltaV)
Show your work for further assistance