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September 1, 2014

September 1, 2014

Posted by **Teresa** on Tuesday, March 2, 2010 at 11:07pm.

y=2sin(3x-pi)

- trig -
**Reiny**, Tuesday, March 2, 2010 at 11:22pmIn

y = a sin k(x - ß)

the amplitude is a

the period is 2pi/k or 360º/k

there is a phase shift of ß to the right.

Yours:

y=2sin(3x-pi)

= 2sin 3(x - pi/3)

so .....

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