Posted by Abby on .
When you take your 1200 kg car out for a spin, you go around a corner of radius 51 m with a speed of 12 m/s. The coefficient of static friction between the car and the road is 0.88. Assuming your car doesn't skid, what is the force exerted on it by static friction?
You will need to show some work for further assistance.
The static friction force provides the centripetal force needed to turn on an unbanked road. With no slipping, it will be less than or equal to the maximum possible static friction, which is 0.88 Mg in this case.