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Posted by on Tuesday, March 2, 2010 at 8:29pm.

The aquation of tris(1, 10-phenanthroline)iron(II) in acid solution takes place according to the equation:
Fe(phen)3^2+ + 3H3O + 3H2O==> (Fe(H2O)6^2+ + 3 phenH^+

If the activation energy is 126 kJ/mol and frequency factor is 8.62 x 1017 s-1, at what temperature is the rate constant equal to 3.63 x 10-3 s-1 for the first-order reaction?

  • Chemistry - , Tuesday, March 2, 2010 at 8:58pm

    I believe ln k = (-Ea/RT) + ln A
    Ea is the activation energy in jouls/mol
    R is 8....
    A is the frequency factor. Solve for T.

  • Chemistry - , Tuesday, March 2, 2010 at 9:21pm

    i keep getting 32.3005 for T, if you have worked it out did you use 8.314472 for R, also is -126kj/mol -12600j/mol?

  • Chemistry - , Tuesday, March 2, 2010 at 9:44pm

    Yes, 8.314 is R but 126 kJ/mol = 126,000 J/mol.

  • Chemistry - , Tuesday, March 2, 2010 at 9:57pm

    ok the answer i got now was 50 degrees celcius

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