Chemistry
posted by Confused .
The aquation of tris(1, 10phenanthroline)iron(II) in acid solution takes place according to the equation:
Fe(phen)3^2+ + 3H3O + 3H2O==> (Fe(H2O)6^2+ + 3 phenH^+
If the activation energy is 126 kJ/mol and frequency factor is 8.62 x 1017 s1, at what temperature is the rate constant equal to 3.63 x 103 s1 for the firstorder reaction?

I believe ln k = (Ea/RT) + ln A
Ea is the activation energy in jouls/mol
R is 8....
A is the frequency factor. Solve for T. 
i keep getting 32.3005 for T, if you have worked it out did you use 8.314472 for R, also is 126kj/mol 12600j/mol?

Yes, 8.314 is R but 126 kJ/mol = 126,000 J/mol.

ok the answer i got now was 50 degrees celcius