posted by Confused .
The aquation of tris(1, 10-phenanthroline)iron(II) in acid solution takes place according to the equation:
Fe(phen)3^2+ + 3H3O + 3H2O==> (Fe(H2O)6^2+ + 3 phenH^+
If the activation energy is 126 kJ/mol and frequency factor is 8.62 x 1017 s-1, at what temperature is the rate constant equal to 3.63 x 10-3 s-1 for the first-order reaction?
I believe ln k = (-Ea/RT) + ln A
Ea is the activation energy in jouls/mol
R is 8....
A is the frequency factor. Solve for T.
i keep getting 32.3005 for T, if you have worked it out did you use 8.314472 for R, also is -126kj/mol -12600j/mol?
Yes, 8.314 is R but 126 kJ/mol = 126,000 J/mol.
ok the answer i got now was 50 degrees celcius