posted by Kelly on .
2 KClO3(s)--> 2 KCl(s) + 3 O2(g)
How many milliliters of O2 will form at STP from 38.8 g KClO3?
Convert 38.8 g KClO3 to moles. moles = grams/molar mass
Using the coefficients in the balanced equation, convert moles KClO3 to moles oxygen.
Convert moles O2 to liters. liters = mols x 22.4 L/mol = ??
so would the problem be set up as:
(38.8 g KClO3) * (1 mol / 122.5 KClO3) * (2 mol KCL / 3 mol O2) * (22400 mL O2 / 1 mol)
(38.8 g KClO3) * (1 mol / 122.5 KClO3) * (3 mol O2 / 2 mol KCl) * 22400 mL O2 / 1 mol) ?