2 KClO3(s)--> 2 KCl(s) + 3 O2(g)
How many milliliters of O2 will form at STP from 38.8 g KClO3?
Convert 38.8 g KClO3 to moles. moles = grams/molar mass
Using the coefficients in the balanced equation, convert moles KClO3 to moles oxygen.
Convert moles O2 to liters. liters = mols x 22.4 L/mol = ??
so would the problem be set up as:
(38.8 g KClO3) * (1 mol / 122.5 KClO3) * (2 mol KCL / 3 mol O2) * (22400 mL O2 / 1 mol)
or
(38.8 g KClO3) * (1 mol / 122.5 KClO3) * (3 mol O2 / 2 mol KCl) * 22400 mL O2 / 1 mol) ?
To find out how many milliliters of O2 will form at STP from 38.8 g of KClO3, we'll need to follow these steps:
Step 1: Convert mass of KClO3 to moles
First, we need to convert the mass of KClO3 to moles by using its molar mass. The molar mass of KClO3 can be calculated by summing the atomic masses of potassium (K), chlorine (Cl), and three oxygen (O) atoms.
Molar mass of KClO3 = (atomic mass of K) + (atomic mass of Cl) + 3 * (atomic mass of O)
The atomic masses (in grams per mole) are as follows:
- Atomic mass of K = 39.1 g/mol
- Atomic mass of Cl = 35.5 g/mol
- Atomic mass of O = 16.0 g/mol
Now, calculate the molar mass of KClO3 and use it to convert grams to moles:
Molar mass of KClO3 = (39.1 g/mol) + (35.5 g/mol) + 3 * (16.0 g/mol)
Molar mass of KClO3 = 122.55 g/mol
Moles of KClO3 = Mass of KClO3 / Molar mass of KClO3
Moles of KClO3 = 38.8 g / 122.55 g/mol
Step 2: Use stoichiometry to find moles of O2
Next, we'll use the balanced equation to determine the mole ratio between KClO3 and O2. From the balanced equation, we know that 2 moles of KClO3 react to produce 3 moles of O2.
So, Moles of O2 = Moles of KClO3 * (3 moles O2 / 2 moles KClO3)
Step 3: Convert moles of O2 to volume at STP
In the last step, we'll convert moles of O2 to volume at standard temperature and pressure (STP).
At STP, 1 mole of any ideal gas occupies 22.4 liters (or 22,400 milliliters).
So, the volume of O2 at STP = Moles of O2 * 22,400 mL/mol
Now, plug in the value of Moles of O2 from the previous step to calculate the volume of O2 at STP.
I'll calculate it for you.