Calculate the molality (m) of a 8280 g sample of a solution of the solute CH2Cl2 dissolved in the solvent (C2H5)2O if the sample contains 13.6 mol of CH2Cl2
See the later post. Same exercise.
To calculate the molality (m) of a solution, you need to use the formula:
m = (moles of solute)/(mass of solvent in kg)
In this case, the solute is CH2Cl2 and the solvent is (C2H5)2O. You are given that there are 13.6 mol of CH2Cl2.
First, calculate the mass of the solvent in kg. The mass of the solution is given as 8280 g.
To convert grams to kilograms, divide the mass by 1000:
mass of solvent = 8280 g ÷ 1000 = 8.28 kg
Now, you can substitute the values into the formula:
m = 13.6 mol / 8.28 kg
Simplify the equation:
m ≈ 1.64 mol/kg
Therefore, the molality (m) of the solution is approximately 1.64 mol/kg.