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April 18, 2014

April 18, 2014

Posted by **josh** on Monday, March 1, 2010 at 9:37pm.

= 2.72 x 10^11

solve for x

- algebra -
**drwls**, Monday, March 1, 2010 at 9:44pmRewrite it as

4x^2 = (10.88 x 10^11)(1.5-x)(1-x)^2

I graphicsl or iterative solution may be necessary, since this is a cubic equation. I suspect that the roots are very close to 1.5 and 1.0

- algerbra -
**josh**, Monday, March 1, 2010 at 10:03pmyou helped me with this chem ques and you got close to 1 how did u get it please help me?You end up with a cubic equation for x. You may have to solve it graphically. Take the root that is between 0 and 1.

As x -> 1, the term on the left approaches

4/[(0.5)(2-2x)^2 ] = 2.27*10^11

2/(1-x)^2 = 2.27*10^11

(1-x) = 3*10^-6

x = 0.999997

You are left with 0.500003 moles O2 and

10^-5 moles CO (the limiting reactant). 1.99999 moles of CO2 are formed

This reaction will, however, be very slow at room temperature. The reaction does not proceed kinetically as written, and requires some O or OH as a chain carrier.

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