Sunday

April 20, 2014

April 20, 2014

Posted by **Samuel** on Monday, March 1, 2010 at 9:27pm.

- Calculus -
**bobpursley**, Monday, March 1, 2010 at 9:46pmdraw the diagram.

I see this

d= sqrt(ND^2+(WD+20)^2) where ND is north distance, WD is west distance

take the derivative

d'= 1/2 *1/(sqrt( ) * 2ND*ND'+2(WD+20)(WD')

ND= 17kt/hr*5hrs ND'=17kts/hr

WD=23*5 WD'=23

have fun.

- Calculus -
**Nathan**, Monday, March 1, 2010 at 10:00pmwhat do you mean by 1/(sqrt()?

- To:bobpursley -
**Nathan**, Monday, March 1, 2010 at 10:04pmwhat do you mean by 1/(sqrt()?

**Related Questions**

calculus - At noon, ship A is 30 nautical miles due west of ship B. Ship A is ...

Calculus - At noon, ship A is 30 nautical miles due west of ship B. Ship A is ...

calculus - At noon, ship A is 10 nautical miles due west of ship B. Ship A is ...

calculus - At noon, ship A is 10 nautical miles due west of ship B. Ship A is ...

CALCULUS - At noon, ship A is 40 nautical miles due west of ship B. Ship A is ...

calculus 1 - At noon, ship A is 50 nautical miles due west of ship B. Ship A is ...

Cal 1 - (1 pt) At noon, ship A is 50 nautical miles due west of ship B. Ship A ...

Calculus - At noon, ship A is 20 nautical miles due west of ship B. Ship A is ...

calculus 1 - At noon, ship A is 20 nautical miles due west of ship B. Ship A is ...

math - At noon, ship A is 40 nautical miles due west of ship B. Ship A is ...