Homework Help: Calculus

Posted by Samuel on Monday, March 1, 2010 at 9:27pm.

At noon, ship A is 20 nautical miles due west of ship B. Ship A is sailing west at 23 knots and ship B is sailing north at 17 knots. How fast (in knots) is the distance between the ships changing at 5 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)

Calculus - bobpursley, Monday, March 1, 2010 at 9:46pm
draw the diagram.

I see this

d= sqrt(ND^2+(WD+20)^2) where ND is north distance, WD is west distance
take the derivative

d'= 1/2 *1/(sqrt( ) * 2ND*ND'+2(WD+20)(WD')

ND= 17kt/hr*5hrs ND'=17kts/hr
WD=23*5 WD'=23

have fun.
Calculus - Nathan, Monday, March 1, 2010 at 10:00pm
what do you mean by 1/(sqrt()?
To:bobpursley - Nathan, Monday, March 1, 2010 at 10:04pm
what do you mean by 1/(sqrt()?

Answer this Question

Related Questions

Calculus - At noon, ship A is 20 nautical miles due west of ship B. Ship A is ...
calculus 1 - At noon, ship A is 20 nautical miles due west of ship B. Ship A is ...
calculus - At noon, ship A is 10 nautical miles due west of ship B. Ship A is ...
calculus - At noon, ship A is 10 nautical miles due west of ship B. Ship A is ...
CALCULUS - At noon, ship A is 40 nautical miles due west of ship B. Ship A is ...
Calculus - At noon, ship A is 10 nautical miles due west of ship B. Ship A is ...
Calculus - At noon, ship A is 10 nautical miles due west of ship B. Ship A is ...
calculus 1 - At noon, ship A is 30 nautical miles due west of ship B. Ship A is ...
calculus 1 - At noon, ship A is 50 nautical miles due west of ship B. Ship A is ...
calculus - At noon, ship A is 30 nautical miles due west of ship B. Ship A is ...

For Further Reading

First Name:
School Subject:
Answer: