if you started with 2.154g of aluminum, how many grams of aluminum oxide would you get?
1. Write and balance the equation.
4Al + 3O2 ==> 2Al2O3
2. Convert 2.154 g Al to moles. mole s= grams/molar mass
3. Using the coefficients in the balanced equation, convert moles Al to moles Al2O3.
4. Now convert moles Al2O3 to grams. g = moles x molar mass.
6.15x 10^27 moles Al2O3= g Al2O3
To determine the number of grams of aluminum oxide you would get, we first need to understand the chemical formula for aluminum oxide. Aluminum oxide is composed of two atoms of aluminum (Al) and three atoms of oxygen (O), so its formula is Al2O3.
To calculate the number of grams of aluminum oxide, we need to consider the molar masses of aluminum (Al) and oxygen (O). The molar mass of aluminum is approximately 26.98 g/mol, and the molar mass of oxygen is approximately 16.00 g/mol.
Since the formula of aluminum oxide contains two atoms of aluminum, we need to multiply the molar mass of aluminum by 2 (Al2). Similarly, since the formula contains three atoms of oxygen, we multiply the molar mass of oxygen by 3 (O3).
Now, let's calculate the molar mass of aluminum oxide:
(2 * molar mass of aluminum) + (3 * molar mass of oxygen)
= (2 * 26.98 g/mol) + (3 * 16.00 g/mol)
= 53.96 g/mol + 48.00 g/mol
= 101.96 g/mol
The molar mass of aluminum oxide is approximately 101.96 g/mol.
Next, we can use this molar mass to calculate the grams of aluminum oxide obtained from the given 2.154 grams of aluminum.
To do this, we need to set up a proportion, establishing the relationship between the molar mass of aluminum oxide and the given mass of aluminum.
(molar mass of aluminum oxide / 1 mol) = (given mass of aluminum / molar mass of aluminum)
Let's calculate the grams of aluminum oxide:
(molar mass of aluminum oxide / 1 mol) = (given mass of aluminum / molar mass of aluminum)
(101.96 g/mol / 1 mol) = (2.154 g / 26.98 g/mol)
= 0.075 g
Therefore, starting with 2.154 grams of aluminum, you would obtain approximately 0.075 grams of aluminum oxide.