if you started with 2.154grams of al, how much of product of aluminum oxide would you expect?

To calculate the amount of product, aluminum oxide, you would expect to obtain from starting with 2.154 grams of aluminum (Al), we need to know the balanced chemical equation for the reaction involving aluminum formation.

Aluminum reacts with oxygen (O₂) to form aluminum oxide (Al₂O₃) according to the following balanced equation:

4 Al + 3 O₂ → 2 Al₂O₃

From the balanced equation, we can see that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide.

To find the amount of aluminum oxide formed in grams, we need to follow these steps:

Step 1: Convert the given mass of aluminum (2.154 grams) to moles.
To convert grams to moles, we need to divide the given mass (in grams) by the molar mass of aluminum (26.98 g/mol).

Molar mass of Al = 26.98 g/mol
Moles of Al = Given mass of Al (in grams) / Molar mass of Al

Step 2: Use the mole ratio from the balanced equation to find the moles of aluminum oxide formed.
From the balanced equation, we know that 4 moles of Al react to form 2 moles of Al₂O₃.

Moles of Al₂O₃ formed = (Moles of Al / 4) * 2

Step 3: Convert the moles of aluminum oxide to grams.
To convert moles of aluminum oxide to grams, we need to multiply the moles by the molar mass of aluminum oxide (101.96 g/mol).

Molar mass of Al₂O₃ = 101.96 g/mol
Grams of Al₂O₃ formed = Moles of Al₂O₃ * Molar mass of Al₂O₃

By following the above steps, you can calculate the amount of aluminum oxide that you would expect to obtain from starting with 2.154 grams of aluminum.