chemistry
posted by supaflychic101 on .
A 1 L flask is filled with 1.40 g of argon at 25 degrees celcius. A sample of ethane vapor is added to the same flask until the total pressure is 1.00 atm.
Whatis the total pressure of Argon in the flask ?
What is the partial pressure of ethane in the flask?

Use PV = nRT to calculate the pressure of Ar in the flask at the beginning.
Then total pressure = partial pressure Ar + partial pressure ethane. 
Please, can you give the answer???
i want to double check 
the partial pressure of Argon is .888 atm

1. PV=nRT
Par(1L)=(0.035mol)(0.0821)(25+273)
=0.856 atm
2.Ptotal = Par + Pethane
Pethane= 1.00atm0.856atm
= 0.144atm