Posted by **Ana** on Monday, March 1, 2010 at 6:38pm.

how do i solve these two problems?

3log(base5)^(x^2+9)-6 = 0

log(base8)^(n-3) + log(base8)^n+4)= 1

can you tell me step by step as well as the answers? please and thank you

- Algebra 2 -
**drwls**, Monday, March 1, 2010 at 7:12pm
Here is how to do the first one. The second is similar. First simplify the algebra. Then write the log equation in a different form.

3 log(base5)^(x^2+9) = 6

log(base5)^(x^2+9) = 2

Which is another way of saying:

5^2 = 25 = x^2 + 9

x^2 = 16

x = + or - 4

- Algebra 2 -
**Ana**, Monday, March 1, 2010 at 7:15pm
how'd you get the log(base5)^(x^2+9) = 2 ?

- Algebra 2 -
**drwls**, Monday, March 1, 2010 at 7:30pm
I divided both sides of the first equation by 3. It's a perfectly "legal" operation when dealing with algebraic equations.

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