Posted by Ana on Monday, March 1, 2010 at 6:38pm.
how do i solve these two problems?
3log(base5)^(x^2+9)-6 = 0
log(base8)^(n-3) + log(base8)^n+4)= 1
can you tell me step by step as well as the answers? please and thank you
- Algebra 2 - drwls, Monday, March 1, 2010 at 7:12pm
Here is how to do the first one. The second is similar. First simplify the algebra. Then write the log equation in a different form.
3 log(base5)^(x^2+9) = 6
log(base5)^(x^2+9) = 2
Which is another way of saying:
5^2 = 25 = x^2 + 9
x^2 = 16
x = + or - 4
- Algebra 2 - Ana, Monday, March 1, 2010 at 7:15pm
how'd you get the log(base5)^(x^2+9) = 2 ?
- Algebra 2 - drwls, Monday, March 1, 2010 at 7:30pm
I divided both sides of the first equation by 3. It's a perfectly "legal" operation when dealing with algebraic equations.
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